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Error Expression Cannot Be Used As A Function C++

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Teenage daughter refusing to go to school more hot questions question feed lang-cpp about us tour help blog chat data legal privacy policy work here advertising info mobile contact us feedback This tells the compiler there is a function what with 3 int arguments. Join them; it only takes a minute: Sign up “cannot be used as a function” error up vote -2 down vote favorite Please have a look at the following code #include Browse other questions tagged c++ cygwin or ask your own question. this contact form

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Error Expression Cannot Be Used As A Function C++

No new replies allowed. This is of course nonsense. The function it says cannot be used is the growthRate function and the estimatedPopulation function.

How to use namedpipe as temporary file? You forgot the multiplication: ((5 / 9) * (fahrenheit - 32)) share|improve this answer answered Nov 26 '13 at 9:29 SingerOfTheFall 18.3k53672 add a comment| up vote 3 down vote You've I pass some of the functions into other functions and am not sure if I am doing it correctly. Variable Cannot Be Used As A Function Today's Topics Dream.In.Code > Programming Help > C and C++ error: cannot be used a function Page 1 of 1 New Topic/Question Reply 2 Replies - 17785 Views - Last Post:

Look at main where the estimate... Cannot Be Used As A Function Arduino and what am I doing wrong? thanks 06-01-2006 #2 hk_mp5kpdw View Profile View Forum Posts Registered User Join Date Jan 2002 Location Northern Virginia/Washington DC Metropolitan Area Posts 3,817 Code: switch(sort){ case 'q': if(stl) sort(my_vect.begin(), my_vect.end()); Possible http://stackoverflow.com/questions/12771933/cannot-be-used-as-a-function-error Why put a warning sticker over the warning on this product?

You're not multiplying in the return statement, so the compiler interprets the second parentheses as a funciton call (that is, calling 5 / 9 with arguments fahrenheit - 32). Rand Cannot Be Used As A Function C++ Thanks in advance for any advice. #include using namespace std; double celsiusFunction(double fahrenheit); int main() { double fahrenheitTemp; fahrenheitTemp = celsiusFunction(99); cout << fahrenheitTemp; return 0; } double celsiusFunction(double fahrenheit) Singular cohomology and birational equivalence Player claims their wizard character knows everything (from books). Please help!

Cannot Be Used As A Function Arduino

Not the answer you're looking for? http://www.dreamincode.net/forums/topic/90425-error-cannot-be-used-a-function/ Lastly, never name your variables and your functions using the same name. Error Expression Cannot Be Used As A Function C++ Did you by chance forgot the multiplication sign i.e.: ((5 / 9)*(fahrenheit - 32)) –skwee357 Nov 26 '13 at 9:29 Also note that (5/9) will be 0 because it Expression Cannot Be Used As A Function Arduino If they do, I ask them to find the smallest example that exhibits the problem and send me that.

Getting started with C or C++ | C Tutorial | C++ Tutorial | C and C++ FAQ | Get a compiler | Fixes for common problems Thread: Compile problem: sort() cannot I am new to C++ anyway. Why don't we use the étale definition of sheaves in Algebraic Geometry Center trace between two pads n-dimensional circles! What exactly are sleeping stalls versus waiting-rooms, for airport layovers? Cannot Be Used As A Function Mathematica

Is This A Good Question/Topic? 1 Back to top MultiQuote Quote + Reply Replies To: error: cannot be used a function #2 polymath D.I.C Addict Reputation: 53 Posts: 670 Joined: Why do you use pointer semantic at all? 1
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class Random { std::mt19937 gen; std::uniform_real_distribution<> distr; public: Random (int seed, double min, double max) : gen(seed), distr(min, max) {} double GenerateNext() error: '...' cannot be used as a function P: 1 Wilhelm1892 I am having these errors: program6.cpp: In function ‘void handleButton(int, int, int, int)’: program6.cpp:176:40: error: ‘incolormenuindex’ cannot be used as navigate here Why are Squibs not notified by the Ministry of Magic Is it possible to write division equation in more rows?

more stack exchange communities company blog Stack Exchange Inbox Reputation and Badges sign up log in tour help Tour Start here for a quick overview of the site Help Center Detailed Exit Cannot Be Used As A Function when i comment out the line that calls sort() everything works fine... It's quick & easy.

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How can I prove its value? Similar topics How to fix "assigned a value that is never used " error? Should I put it in every .cpp file instead? –darko Dec 10 '10 at 20:41 See stackoverflow.com/questions/1452721/… –Johnsyweb Dec 11 '10 at 10:08 add a comment| 6 Answers 6 C++ Time Cannot Be Used As A Function Is it possible to bleed brakes without using floor jack?

Newton's second law for individual forces What is the definition of "rare language"? thank you! Rename the local variable. Teenage daughter refusing to go to school Player claims their wizard character knows everything (from books).

While it won't do what is desired, as ^ is not exponentiation and the resulting equation is nonsense, it should parse and compile. YOu need a function prototype: Expand|Select|Wrap|Line Numbers intwhat(intx,inty,intz); intmain() { what(9,3,17);//thisisnowOK } The function prototype is the first line of the function definition ended by a semicolon. share|improve this answer edited Oct 7 '12 at 19:26 answered Oct 7 '12 at 19:13 Griwes 5,97121858 add a comment| up vote 0 down vote You should probably read some examples Try changing the name of the variable in your code to something else. "Owners of dogs will have noticed that, if you provide them with food and water and shelter and

PHP Fatal error: Cannot access empty property error cannot find function bounds DataColumn.Expression Error - 'Cannot Find Column [ColumnName]' Error - Cannot call member function without object... The code listed below and also available @ cpp.sh/4hte. help! The int what outside of main is completely blocked by this local one.

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