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Cannot Convert This Pointer From Const To &


c++ c++11 const pass-by-reference share|improve this question edited Jul 28 '14 at 4:11 user2864740 35.5k43982 asked Jul 18 '14 at 1:03 KKlouzal 13112 marked as duplicate by Praetorianc++ Users with the Compiler Error C2662 Visual Studio 2015 Other Versions Visual Studio 2013 Visual Studio 2012 Visual Studio 2010 Visual Studio 2008 Visual Studio 2005 Visual Studio .NET 2003  'function' : cannot convert Therefore you can't call non-const method on them. Something that seems trivial and petty to you guys is a whole new thing to me. http://mediastartpage.com/cannot-convert/cannot-convert-from-const-char-to-lpctstr.html

It needs the const there so that it can be sure that the object will not change. Experience is gained from bad judgment. Advanced Search Forum Other General Programming cannot convert 'this' pointer from 'const Square' to 'Square &' If this is your first visit, be sure to check out the FAQ by clicking Apr 6 '07 #3 reply Expert Mod 5K+ P: 8,916 Banfa error C2662: 'std::vector<_Ty>::push_back' : cannot convert 'this' pointer from 'const std::vector<_Ty>' to 'std::vector<_Ty> &' with [ _Ty=std::string ] and [ http://stackoverflow.com/questions/12068301/c-error-c2662-cannot-convert-this-pointer-from-const-type-to-type

Cannot Convert This Pointer From Const To &

since you're one of the guys who is always correcting me, suggest one that stands out of that list (I've seen that list a few times) and I'll buy it. Reply With Quote March 6th, 2007,08:14 AM #8 cilu View Profile View Forum Posts Visit Homepage Elite Member Power Poster Join Date Oct 2002 Location Timisoara, Romania Posts 14,360 Re: error How to NOT render a part of a document more hot questions question feed lang-cpp about us tour help blog chat data legal privacy policy work here advertising info mobile contact Post your question and get tips & solutions from a community of 418,747 IT Pros & Developers.

Powered by vBulletin Version 4.1.9 Copyright ©2000 - 2016, Jelsoft Enterprises Ltd., © 2006–2010 Qt Centre - The Ultimate Qt Community site Nokia and its respective logos are trademarks of Nokia As far as I know you cannot call a constructor directly. What now? Const Function My homepage Advice: Take only as directed - If symptoms persist, please see your debugger Linus Torvalds: "But it clearly is the only right way.

I am a beginner so go easy with the exclamation marks... *hints at cilu*. c++ compiler-errors share|improve this question edited Apr 15 '13 at 15:45 Rachel Gallen 14k123858 asked Jul 8 '11 at 2:29 Casey 3,49033058 @iammilind: He has the prototype in his Player claims their wizard character knows everything (from books). add a comment| 1 Answer 1 active oldest votes up vote 5 down vote accepted The problem is that in the callback, the DataPacket object Packet is marked as const.

Good judgment is gained from experience. Const Correctness Safely adding insecure devices to my home network How can I check that the voltage output from this voltage divider is 2.25V? const A& a = ...; a.foo(); // failed That's what const aimed for: a const variable means, it is declared not going to be changed. Your constructor is being passed a vector by value.

Const Method

But with those more 'acrane' rules of C++ I am never sure. http://forums.codeguru.com/showthread.php?416873-RESOLVED-error-C2662-cannot-convert-this-pointer-from-const-Item-to-Item-amp No new replies allowed. Cannot Convert This Pointer From Const To & Browse other questions tagged c++ operator-overloading syntax-error friend-function or ask your own question. Error C2662 Cannot Convert This Pointer From Const To Conversion Loses Qualifiers Reply With Quote 2nd August 2006,17:19 #9 Kumosan View Profile View Forum Posts View Blog Entries View Articles Intermediate user Join Date Aug 2006 Posts 221 Thanks 3 Thanked 29 Times

asked 5 years ago viewed 29324 times active 25 days ago Get the weekly newsletter! weblink You are currently viewing our boards as a guest which gives you limited access to view most discussions and access our other features. Possible resolutions:Remove the const from the object declaration.Add const to the member function.The following sample generates C2662: Copy // C2662.cpp class C { public: void func1(); void func2() const{} } const can someone please explain to me WHY it's giving me this error... Const_cast Example

more stack exchange communities company blog Stack Exchange Inbox Reputation and Badges sign up log in tour help Tour Start here for a quick overview of the site Help Center Detailed Depalindromize this string! I don't know why it converts to lowercase on copy&paste. navigate here cannot convert '*this' from 'const Foo' to 'Foo &' Originally Posted by tabstop I got a slightly more helpful warning message from gcc: error: no matching function for call to `Foo::foo1()

Cheers Huck Reply Quote 0 thisisbhaskar last edited by Your removeDataItem() is const function, and its trying to remove/modify your class member variable. Const C++ Or is it? Reply With Quote March 6th, 2007,09:15 AM #10 Paul McKenzie View Profile View Forum Posts Elite Member Power Poster Join Date Apr 1999 Posts 27,449 Re: error C2662: cannot convert 'this'

Could I work as a Professor in Europe if I only speak English?

Plz help, me=noob By rrum in forum C++ Programming Replies: 7 Last Post: 12-01-2005, 12:09 AM Question About Pointer To Pointer By BlitzPackage in forum C++ Programming Replies: 2 Last Post: Experience is gained from bad judgment. Am I interrupting my husband's parenting? This is exactly what's going on here.

The time now is 12:15 AM. Just to make a note, if you have a method which is conceptually constant, but still needs to change some private state, consider using the mutable keyword. contact us Navigation Qt Forum Login Search Search Categories Recent Tags Popular Groups Search Your browser does not seem to support JavaScript. his comment is here And since you just corrected his code that much that it compiles without warning him again to fix his constructor, I just got more unsure.

current community chat Stack Overflow Meta Stack Overflow your communities Sign up or log in to customize your list. error C2662: 'CombatEvent::getType' : cannot convert 'this' pointer from 'const CombatEvent' to 'CombatEvent &' this error is at this line if (lhs.getType() == rhs.getType()) see the code bellow: class CombatEvent { Why put a warning sticker over the warning on this product? Center trace between two pads How can ransomware know file types?

Instead declare the function as int GetData() const; share|improve this answer edited Jul 18 '14 at 1:19 answered Jul 18 '14 at 1:11 Some programmer dude 214k16147259 Thank you Forum Today's Posts C and C++ FAQ Forum Actions Mark Forums Read Quick Links View Forum Leaders What's New? Word for "using technology inappropriately"? Consider that if you had a const int, you couldn't pass it to a function void (int &), because it requires that the parameter be non-const.

Remove const. Is it acceptable to ask an unknown professor for help in a related field during his office hours? How do I reverse this javascript code? Powered by vBulletin Version 4.2.3 Copyright © 2016 vBulletin Solutions, Inc.

If I'm missing anything out let me know! No the method might be non const as well. Good judgment is gained from experience. Making ContainsPoint a const method will cause a chain reaction in the code of const-ing every subsequent method.

Results 1 to 11 of 11 Thread: [RESOLVED] error C2662: cannot convert 'this' pointer from 'const Item' to 'Item &' Tweet Thread Tools Show Printable Version Email this Page… Subscribe to One Very Odd Email Newton's second law for individual forces What exactly are sleeping stalls versus waiting-rooms, for airport layovers? And if I remember right, a const method can accept non-const reference but the converse is not true. –Andrew White Jul 8 '11 at 2:54 @Casey: That's pretty much How to harness Jupiter's gravitational energy?

asked 2 years ago viewed 1517 times active 2 years ago Linked 17 c++ error C2662 cannot convert 'this' pointer from 'const Type' to 'Type &' Related 2C++ const iterator C266217How Does トイレ refer to the British "toilet" or the American "toilet"? c++ operator-overloading syntax-error friend-function share|improve this question asked Aug 22 '12 at 7:33 thiagoh 1,77262144 add a comment| 3 Answers 3 active oldest votes up vote 36 down vote accepted CombatEventType isxvd = plxisxvd->PMin()[iDim]; isxvd = plxisxvd->PMin2()[iDim]; } Show: Inherited Protected Print Export (0) Print Export (0) Share IN THIS ARTICLE Is this page helpful?

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